0=0.002x^2+.5x-148.5

Solution for 0=0.002x^2+.5x-148.5 equation:

0=0.002x^2+.5x-148.5

We move all terms to the left:

0-(0.002x^2+.5x-148.5)=0

We add all the numbers together, and all the variables

-(0.002x^2+.5x-148.5)=0

We get rid of parentheses

-0.002x^2-.5x+148.5=0

We add all the numbers together, and all the variables

-0.002x^2-0.5x+148.5=0

a = -0.002; b = -0.5; c = +148.5;
Δ = b2-4ac
Δ = -0.52-4·(-0.002)·148.5
Δ = 1.438
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{1.438}}{2*-0.002}=\frac{0.5-\sqrt{1.438}}{-0.004}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{1.438}}{2*-0.002}=\frac{0.5+\sqrt{1.438}}{-0.004}
$